If it's not what You are looking for type in the equation solver your own equation and let us solve it.
w^2+15w-126=0
a = 1; b = 15; c = -126;
Δ = b2-4ac
Δ = 152-4·1·(-126)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-27}{2*1}=\frac{-42}{2} =-21 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+27}{2*1}=\frac{12}{2} =6 $
| 12t+4.9t^{2}=5.8 | | 9(x−1)=2, | | 9x+2=14x-7 | | 18+9=x-9 | | 12.1t+4.9t^{2}=5.8 | | 18+9=x-19 | | 18+x=14+x | | 5x+15+-5+7x=180 | | 8h=2h-24 | | 49h-200=0 | | A=1/2(10d) | | (1/3)^2x+3=9^x-5 | | 2x+20°=x+70° | | 9x=20=3+16 | | 10(10x-6)-4(6-5x)+3(-6x+2)=-9(6-5x) | | -u/6=-40 | | 58=-w+167 | | -21=-1/10j | | M3=3x+12 | | 2m/5-3/2=m/2+1 | | P-3/5-2=2p/5 | | 9x2-12x=-9 | | 4y/3+8=20 | | a/4=7=12 | | h+12-8=24 | | 1/2(2x+3)=20 | | (2k)^3-2(2k)+3=2k+1 | | 4/3x–7=2x–3 | | 0.6x0.003= | | 7.5/x=3/4 | | 7.5/x=2 | | 12x+6=4x=12 |